Wrestler Reetika Hooda eliminated in Paris Olympics quarter-final match.

Indian wrestler Reetika Hooda lost a close quarter-final bout against Kyrgyzstan's Aiperi Medet Kyzy in the women's 76 kg freestyle category at the Paris Olympics. Despite a 1-1 tie, Kyrgyzstan won due to the last equalizing point.

August 10th 2024.

Wrestler Reetika Hooda eliminated in Paris Olympics quarter-final match.
In the bustling city of Paris, the highly anticipated women's 76 kg freestyle wrestling quarter-final match between Indian wrestler Reetika Hooda and Kyrgyzstan's Aiperi Medet Kyzy took place at the Paris Olympics on Saturday. It was a nail-biting bout that kept the audience on the edge of their seats until the very end.

The two fierce competitors were evenly matched, showcasing top-quality defensive wrestling skills. After six intense minutes of grappling, they were tied at 1-1. However, according to the rules, the Kyrgyz wrestler was declared the winner as she scored the last equalizing point.

Throughout the match, both wrestlers played a defensive game, resulting in only one point each being scored through passivity in the two periods. Reetika now has to wait for Kyzy to potentially make it to the final, which would give her a chance to compete in the repechage round.

But if Kyzy doesn't advance to the final, India's Paris Games journey will come to an end with a total of six medals, unfortunately without a gold. However, Reetika's impressive performance in the pre-quarterfinals against Bernadett Nagy of Hungary, where she won 12-2, proved her power and skill in equal measure.

As the thrilling Olympic games continue, we can't wait to see what other amazing performances will come from these talented athletes. And for Reetika, we wish her the best of luck in her future endeavors.

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